CLASS RACER FORUM
Page 2 of 3 1 2 3
Show 40 post(s) from this thread on one page

CLASS RACER FORUM (https://classracer.com/classforum/index.php)
-   Stock and Super Stock (https://classracer.com/classforum/forumdisplay.php?f=3)
-   -   Need a little Math Help (https://classracer.com/classforum/showthread.php?t=58039)

Spyphish 05-18-2015 05:38 PM
Re: Need a little Math Help
 
Jeff, you need Jethro!!! Remember when Jed asked him to cipher since he was in Beverly Hills school.


Naught plus naught = naught
Naught minus naught = naught
Naught times naught = naught


Naught divided by naught = naught??????


Not really, that's undefined. But it made a great show.


See you in two weeks at BR?

Larry Sullivan 05-18-2015 05:39 PM
Re: Need a little Math Help
 
Quote:
Originally Posted by HawkBrosMav (Post 470963)
I also got .547 inches..


Not to completely over complicate things but I've always wanted to know what others think about how the difference in speeds of the 2 cars would change this calculation? Or if we know one or both guy(s) was/were on the brakes does the computer system give us enough info to accurately calculate this distance? Would we not actually want to know the rate of acceleration not the measured MPH to get this distance totally correct? or am I just over thinking it?


the .547 in a very good estimate to me but is it truly the distance between the 2 cars when the first one crosses the finish line?


Brad
All you need is the speed of the losing car since that''s how far he was behind when the winner broke the beam. Assuming the speed isn't changing very much in the last 66 feet, of course.

Greenlight 05-18-2015 06:25 PM
Re: Need a little Math Help
 
Remember, that the speed is now calculated as an average speed using timers at a distance 66 feet before the finish line, and the timer at the finish line.

So, he was probably actually going quicker than 141.5 at the finish line.

But, using 141.5 mph = 207.5383 ft/sec.

2/10000 seconds times 207.5383 ft/sec = 0.041508 ft.

0.041508 ft times 12 inches/ft = 0.498 inches.

At 143 MPH it is 0.503 inches.


*In the old days there was a timer 66 ft. before the finish line and one 66 ft. after the finish line. The average time was a lot closer to the actual finish line MPH back then.

SSDiv6 05-18-2015 08:34 PM
Re: Need a little Math Help
 
Taking into consideration the car is accelerating, the result is 0.4980 inches.

Bobby Brannon 05-18-2015 09:03 PM
Re: Need a little Math Help
 
Just saying. 3856 MOV. 3/4" of inch
but I am old

HR9121 05-18-2015 10:22 PM
Re: Need a little Math Help
 
A little more than a split frog's hair would be a guesstimate.

dartman 05-19-2015 02:26 PM
Re: Need a little Math Help
 
the answer is 0.50336

Frank B. 05-19-2015 05:09 PM
Re: Need a little Math Help
 
My answer is at 141.58 for the second car to cross with a MOV of .00022 the distance would be .548197 or 8.7711 16s of an inch. I stayed at a Holiday Inn Express last night also.lol

John Dinkel 05-19-2015 05:44 PM
Re: Need a little Math Help
 
At that speed how much Labatt beer can you drink?

tim worner 05-19-2015 06:21 PM
Re: Need a little Math Help
 
After a lot of deliberation I would say it was pretty darn close.


All times are GMT -4. The time now is 01:00 PM.
Page 2 of 3 1 2 3
Show 40 post(s) from this thread on one page

Powered by vBulletin® Version 3.8.11
Copyright ©2000 - 2025, vBulletin Solutions Inc.
Copyright Class Racer.com. All Rights Reserved. Designated trademarks and brands are the property of their respective owners.