Need a little Math Help
How much distance does a car going 141.5 mph cover in 2/10000 seconds or to be more exact 22/100000 seconds. We are trying to figure it out, but it's a little over our heads.
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Re: Need a little Math Help
need more info ...
you did not factor in any BEER... thats a variable, so its important :) captain jack |
Re: Need a little Math Help
Im going with a un educated guess. .48 of a inch if your stating .0002 (2/10000)
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Re: Need a little Math Help
0.0985 Inches.. Buick math.
Less than a tenth of an inch? |
Re: Need a little Math Help
I got 0.54 inches. Or basically 1/2 inch.
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Re: Need a little Math Help
Capt, no beer that day, maybe that's the trouble. That is what Kevin lost by in Atlanta .0002. So somewhere between a tenth inch and a half inch. I have a comparison to that, but not here. Thanks guys.
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Re: Need a little Math Help
Using the Kentucky wet finger in the air method I'm a going guess .4980792". I apologize that I was unable to get my shoes off (that Velcro is some tuff stuff) to give you a more accurate number!
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Re: Need a little Math Help
I came up with .054 inches. would not be visible by the naked eye with the best cameras. I had a round where both of the cars had exactly the same RT to the thousandth and ran exactly the same over our dials to the thousandth. I won the round. not sure how the computer picked the winner. We both just shook our heads on that run.
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Re: Need a little Math Help
I also got .547 inches..
Not to completely over complicate things but I've always wanted to know what others think about how the difference in speeds of the 2 cars would change this calculation? Or if we know one or both guy(s) was/were on the brakes does the computer system give us enough info to accurately calculate this distance? Would we not actually want to know the rate of acceleration not the measured MPH to get this distance totally correct? or am I just over thinking it? the .547 in a very good estimate to me but is it truly the distance between the 2 cars when the first one crosses the finish line? Brad |
Re: Need a little Math Help
Without doing all the conversions to complicate it..
1 mph = 17.6 inches/second So: 141.5*17.6 = 2,490.4 inches/second 2,490*(2/10000) = 0.498 inches My guess anyway. |
Re: Need a little Math Help
Jeff, you need Jethro!!! Remember when Jed asked him to cipher since he was in Beverly Hills school.
Naught plus naught = naught Naught minus naught = naught Naught times naught = naught Naught divided by naught = naught?????? Not really, that's undefined. But it made a great show. See you in two weeks at BR? |
Re: Need a little Math Help
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Re: Need a little Math Help
Remember, that the speed is now calculated as an average speed using timers at a distance 66 feet before the finish line, and the timer at the finish line.
So, he was probably actually going quicker than 141.5 at the finish line. But, using 141.5 mph = 207.5383 ft/sec. 2/10000 seconds times 207.5383 ft/sec = 0.041508 ft. 0.041508 ft times 12 inches/ft = 0.498 inches. At 143 MPH it is 0.503 inches. *In the old days there was a timer 66 ft. before the finish line and one 66 ft. after the finish line. The average time was a lot closer to the actual finish line MPH back then. |
Re: Need a little Math Help
Taking into consideration the car is accelerating, the result is 0.4980 inches.
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Re: Need a little Math Help
Just saying. 3856 MOV. 3/4" of inch
but I am old |
Re: Need a little Math Help
A little more than a split frog's hair would be a guesstimate.
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Re: Need a little Math Help
the answer is 0.50336
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Re: Need a little Math Help
My answer is at 141.58 for the second car to cross with a MOV of .00022 the distance would be .548197 or 8.7711 16s of an inch. I stayed at a Holiday Inn Express last night also.lol
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Re: Need a little Math Help
At that speed how much Labatt beer can you drink?
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Re: Need a little Math Help
After a lot of deliberation I would say it was pretty darn close.
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Re: Need a little Math Help
Jeff, this distance is commonly referred to as an RCH.......just so you know.
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Re: Need a little Math Help
1+1=2
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