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Brister · 10-08-2007, 02:08 PM

If you can't find the website this is the formula I use:

Multiply the mph of the second car to pass the finish line by 63,360 (inches per mile) then divide it by 3,600,000 (thousandths per hour).

You are travelling 1.76" per .001 at 100mph.

100 x 63,360 = 6,336,000 divided by 3,600,000 = 1.76

This is based on a constant speed for the last 66' thus dumping/braking probably throws the formula a little out of whack. Irregardless it's probably pretty accurate and I don't know any other way to figure it.

Anybody else got any better formulas?

10-08-2007, 02:08 PM	#4
Brister Junior Member Join Date: Jan 2007 Location: morehead city, nc Posts: 83 Likes: 0 Liked 6 Times in 3 Posts	Re: web site needed If you can't find the website this is the formula I use: Multiply the mph of the second car to pass the finish line by 63,360 (inches per mile) then divide it by 3,600,000 (thousandths per hour). You are travelling 1.76" per .001 at 100mph. 100 x 63,360 = 6,336,000 divided by 3,600,000 = 1.76 This is based on a constant speed for the last 66' thus dumping/braking probably throws the formula a little out of whack. Irregardless it's probably pretty accurate and I don't know any other way to figure it. Anybody else got any better formulas?