Need a little Math Help

Greenlight · 05-18-2015, 06:25 PM

Remember, that the speed is now calculated as an average speed using timers at a distance 66 feet before the finish line, and the timer at the finish line.

So, he was probably actually going quicker than 141.5 at the finish line.

But, using 141.5 mph = 207.5383 ft/sec.

2/10000 seconds times 207.5383 ft/sec = 0.041508 ft.

0.041508 ft times 12 inches/ft = 0.498 inches.

At 143 MPH it is 0.503 inches.

*In the old days there was a timer 66 ft. before the finish line and one 66 ft. after the finish line. The average time was a lot closer to the actual finish line MPH back then.

05-18-2015, 06:25 PM	#12
Greenlight Member Join Date: Dec 2004 Posts: 216 Likes: 16 Liked 81 Times in 23 Posts	Re: Need a little Math Help Remember, that the speed is now calculated as an average speed using timers at a distance 66 feet before the finish line, and the timer at the finish line. So, he was probably actually going quicker than 141.5 at the finish line. But, using 141.5 mph = 207.5383 ft/sec. 2/10000 seconds times 207.5383 ft/sec = 0.041508 ft. 0.041508 ft times 12 inches/ft = 0.498 inches. At 143 MPH it is 0.503 inches. *In the old days there was a timer 66 ft. before the finish line and one 66 ft. after the finish line. The average time was a lot closer to the actual finish line MPH back then.