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#28 |
Live Reporter
Join Date: Oct 2004
Location: Hickory, Ky
Posts: 10,646
Likes: 1,941
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RJ I have been trying to figure how two .892 width bearing that fit into a rod that is .995 wide fits on the crankpin without interferance.
Lets do the math: BBC rod width .995 X 2 = 1.990 + .015 rod side clearance = 2.005'' FE Ford rod width .868 X 2 = 1.736 + .015 rod side clearance = 1.751'' BBC assembled width of two rods and .015 side clearance 2.005 FE Ford assembled width of two rods and .015 side clearance 1.751 2.005 - 1.751 = .254 interferance. You could not assemble these parts with a four pound hammer. Its kind of humorous to know the width of two stock ( remember Stock) Chevy bearings is .033'' wider than two FE rods. Either the rod was narrowed at the big end or the crank really had to be ground on to make the crankpin wide enough to accept two rods that were 1/4 " wider than OEM. Just a guess but I think the crank lost another pound or so. So did the postman grind on the rod? I would like to buy a new Auccucrank for a 428 and a set of new Dove heads. Let me guess neither are available, but new oem size cranks can still be purchased. I just want the 2.200 crankpins for the FE and 429/460 Fords out of Stock. It was approved for Superstock by NHRA and I don't know S/S rules well enough to discuss the subject. Thanks Dan |
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